Question

A stone is thrown from a 50m tall tower. Another stone is thrown upwards with a velocity of 25m/s. At what distance from the top of the tower will the stone cross each other?

Answer 1

Answer:

let the bottom stone to be at rest.

vel of upper stone= -25j

relative g=0

time taken for balls to meet= 2 sec

dist travelled by upper ball in 2 sec s= 1/2*g*t^2

put t=2 in s

s= 20m

Answer 2

Answer:

24 metre of tower height

Explanation:

because in 1st case stone is thrown from top at front then the gravity will attract it 30km/h will be increased every sec . now in 2nd case a stone is thrown upward at the speed of 25m/s but gravity will attract it by per sec but the will cross it in just one sec but gravity will attract it only one metre