A stone is thrown from the bridge at an angle of 30° down with the horizontal with the velocity of 25 m/s. Calculate the height of bridge from the water surface.
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Answered by
32
Answer:
61.875 m
Explanation:
Given A stone is thrown from at an angle of 30° down with the horizontal with the velocity of 25 m/sec if stone strikes the water after 2.5 sec then calculate the height of bridge from water surface
Let the height be h
Velocity = - 25 sin 30 = -25 /2 = - 12.5 m/s
We know that from equation of motion we get
S = ut + 1/2 at^2
-h = - 12.5 x 2.5 - 1/2 x 9.8 x 2.5^2
-h = - 31.25 – 30.625
h = 61.875 m
the height of bridge from the water surface is 61.875 m
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2
Answer:
anybody give the horizontal range of this question
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