Question

A stone is thrown from the top of a tower of height 29.4 m with velocity 9.8 m/s in a direction making angle 30° with horizontal in downward direction. After how long time and at how much horizontal distance from the tower will the stone ball strike on the earth?
plz help​

Answer 1

Explanation:

Given V=16m/s, time t=4s. Let height h, and Horizontal range R

Velocity in upward direction V

y

=Vsin(30

o

)=8m/s,

Velocity in horizontal V

x

=Vcos(30

o

)=8

3

In upward direction, Using s=ut+

2

1

at

2

⇒h=8×4−

2

1

×9.8×4

2

⇒h=−46.4 , Hence, Height=46.4m,

In horizontal direction, Range=V

x

×t

⇒R=8

3

×4=32

3

m, Hence Range is 32

3

m