A stone is thrown horizontally at a speed of 12.0 m/s from the top of a cliff 92.1 m high. The fall took 4.34 s. How far from the base of the cliff does the stone strike the ground?
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Answer:
Taking the vertical component of motion we can assume that the initial velocity is zero so:
s
=
1
2
g
t
2
∴
t
=
√
2
s
g
t
=
√
2
×
80
9.8
t
=
4.04
s
(b)
The horizontal component of velocity is constant so:
Distance = speed x time
∴
d
=
30
×
4.04
=
121.2
m
Explanation:
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