Question

A stone is thrown horizontally from 2.4 m above the ground at 35
m/s. The wall is 14 m away and 1 m high. At what height the
stone will reach? Where will the stone land?

[answer with solution] ​

Answer 1

Explanation:

Firstly calculate the time taken for the stone to reach the wall.

Distance = speed x time

Therefore time = distance/speed = 14/35 = 0.4 secs.

Apply the formula for gravitational acceleration and distance:

Distance stone will drop in 0.4 sec = 1/2 x g x time^2

= 1/2 x 9.8 x 0.4^2

=0.784m

Therefore the stone will drop 0.784m by the time it passes over the wall, therefore it passes over the wall at a height of 0.616m above the wall.

Where it will land will depend upon the terrain behind the wall. Assuming a flat terrain, we need to calculate the time taken for the stone to drop 2.4m,

Applying the formula again:

Distance = 1/2 x g x time^2

2.4 = 1/2 x 9.8 x time^2

time^2 = 2.4/4.9 = 0.49

time = sqrt 0.49 = 0.7 sec

Therefore, in 0.7 secs at 35m/s, the stone will travel 24.5m.

So the stone will hit flat ground 10.5m (24.5–14) behind the wall.

All the above ignores air resistance, which would slow the stone’s travel both horizontally and vertically.

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