a stone is thrown horizontally from the top of tower 78.4m high with a velocity 20m/s. when and where does the stone hit the ground?
Answers
Answered by
1
Step-by-step explanation:
Answer
For I
st
stone u
h
=10 m/s
u
v
=0;s
v
=−78.4 m;g=−9.8 m/s
2
s
v
=u
v
t+
2
1
at
2
⇒−78.4=
2
−9.8
×t
2
t
2
=16 sec.⇒t=4 sec.
Distance travelled in horizontal direction in 4 s
s
n
=10×4=40 m
For II
nd
stone →u
h
=20 m/s;u
v
=0;s
v
=−78.4 m;g=−9.8 m/s
2
It will also take same time as the vertical distance travelled is same. Distance travelled in horizontal direction by II
nd
stone in 4 s
s
n
=20×48=80 m
total distance between stones =40+80=120 m
Answered by
0
Answer:
Step-by-step explanation:
U=0
S=78.4m
S=ut+1/2at*t
t=4s
Horizontal displacement=20*4
=80m
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