Physics, asked by gokulkrishnan050425, 8 months ago

A stone is thrown horizontally with a speed √2gh from the top of a wall

of height h. It strikes the level ground through the foot of the wall at a

distance x from the wall. What is the value of x?​

Answers

Answered by ReRepeater
1

Explanation:

time taken t= \root 2h/ g

Range = u x t

=√2gh x √2h/ g

= 2h

Similar questions