a stone is thrown horizontally with speed 30m/s from a tower of height 50m. the height of stone from ground at which it makes angle 45 with the horizontal.
Answers
hi,
i am not sure with the answer but still....
height of stone , h = -50m [ taking reference level is at 50m above from ground]
horizontal initial speed of stone , =30m/s.
vertical initial speed of stone , = 0m/s
at ground ,
horizontal speed ,
vertical speed ,
now,
now, stone is projected with speed 10√15 at an angle of projection is 45° with horizontal.
so, maximum height = u²sin²θ/2g
= (1500)² × sin²45°/2 × 10
= (1500) × 1/2/20
= 1500/40
= 37.5 m
thanks,
hope it helps u....
Answer:
hi,
i am not sure with the answer but still....
height of stone , h = -50m [ taking reference level is at 50m above from ground]
horizontal initial speed of stone , =30m/s.
vertical initial speed of stone , = 0m/s
at ground ,
horizontal speed ,
vertical speed ,
now,
now, stone is projected with speed 10√15 at an angle of projection is 45° with horizontal.
so, maximum height = u²sin²θ/2g
= (1500)² × sin²45°/2 × 10
= (1500) × 1/2/20
= 1500/40
= 37.5 m
thanks,
hope it helps u....