Question

a stone is thrown horizontally with the velocity of 15 metre per second from the tower with height of 25 metre.
find
1. the time during which the stone is in motion,
2. the distance from the tower base where the stone will drop into the ground,
3. the velocity with which it will touch the ground,
4.and the angle formed by the trajectory of the stone with the horizontal at the point where it reaches the ground.
Neglect the resistance of air.
(1=2.26s , 2= 33.9m, 3=26.75ms^-1, 4=55°4`)
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Answer 1

Answer:

Range, R=vt=15×2.25=33.75m

Explanation:

Given,

Vertical velocity is zero

Horizontal velocity is v=15m/s

Height, h=25m

Time period t=

g

2h

=

9.81

2×25

=2.25 sec

Range, R=vt=15×2.25=33.75m