Question

A stone is thrown horizontally with tower .in 0.5 sec after the stone began to move the numerical value of its velocity was 1.5 times its initial velocity. find initial velocity

Answer 1

So, as the body was projected horizontally,
Ux = v
Uy=0
(Assuming the initial velocity to be v)
Consider x and y to be standard coordinate axes

Now, there is no acceleration in the x direction, so x component of velocity will remain same throughout the flight
But y component has force of gravity so, it will result in velocity increase
Now,
After 0.5 sec,
Ux=v
For y component,
v=u+ at
a=-10m/s²
So,
v= 0 -10 ×0.5
v=-5 (-ve due to considering the sign conventions)
Vy= 5m/s 
Now,
the velocity after 0.5 sec is 1.5 times the initial velocity
So,
Vnet=1.5v
So,
Vnet=√(Vx² +Vy²)
(Law of vector addition)
1.5v=√(25+ v²)
2.25v² - v² = 25
v²=20
v=4.47 m/s

So, the initial velocity was 4.47 m/s

Answer 2

Answer:

Explanation

Please draw a diagram Soo that u should feel it.....soln is provided in form of image

I hope it will help u

In preparation...