Question

A Stone is thrown in a vertically upwand direction with a velocity of 5ms-¹. If
the acceleration of the stone during its motion lis 10m s-² in the downward direction,what
will be the height attained by the stone and how much time will it take to reach there?​

Answer 1

Answer:

Maximum height=1.25

Time of ascension =0.5 s

Explanation:

H=

$\frac{ {u}^{2} }{2g}$

H=

$\frac{25}{20} = 1.25s$

Time of ascend,Ta=

$\frac{u}{g}$

Ta=

$\frac{5}{10} = 0.5s$

Answer 2

H = u^2 ÷ 2a

H = 1.25

V = U - at

0 = 5 - 10t

t = 0.5 sec