Question

a stone is thrown in a vertically upward direction what will be the height attended by the stone and how much time will it take to reach there​

Answer 1

Answer:

A stone is thrown in vertically upward direction with a velocity of 5ms−1. If the acceleration of the stone during its motion is 10ms−2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there? A. Height = 1.25 m and time 0.5 s.

Answer 2

Answer:

Maximum height = u*t + 1/2*a*t²

Time taken = v-u/+g

Explanation:

Let the velocity by which stone was thrown upward is u. The height be h and the velocity when the stone attains its maximum height is v that will be 0. The time taken by the stone is t and the negative acceleration due to gravity is -g. So, the maximum height attained by the stone is :-

(By second Kinematical equation)

h = u*t + 1/2*a*t²

And the time taken to reach the maximum height is :-

-g = v-u/t

t = v-u/+g