Question

a stone is thrown in a vertically upward direction with a velocity of 5 metre per second if the acceleration of the stone during this motion is 10 metre per second in the downward Direction What will be the height attained by the stone and how much time will it take to reach there​

Answer 1

Answer:

initial velocity (u) = 5m/s

a= -10m/s

s=

v= 0 (because of gravatitational force)

Explanation:

Since v, a and u is given we have to apply

v= u +at to find the time.5+

0= 5+ 10×t

0=5 + -10t

-10t = -5

t= -5/-10 m

= 0.5s

to find distance:

s= ut+ 1/2at²

s= 5×0.5 + 1/2 × 10× 0.5× 0.5

s= 5.5 m.