Question

A stone is thrown in a vertically upward direction with a velocity of 10m
acceleration is 10m/s square in the downward direction. What will be the height attained
by the stone and how much time will it take to reach there?​

Answer 1

Answer:

HEIGHT IS 5m and TIME TAKEN IS 2.41 secs

Explanation:

U = 10 m/s

V = 0 m/s

g=-10m/s

Applying the third equation of motion

v^2=u^2 + 2as

0=100+2×-10s

-100/2×-10=s

s=5 m

TIME TAKEN IS DETERMINED BY USING SECOND EQUATION

s=ut+1/2at^2

5=10t+5t^2

t^2+2t-1=0

t=(2+√8)/2

t=1+√2

t=2.41 secs