A stone is thrown in a vertically upward direction with a velocity of 5m/s . If the acceleration of the stone during its motion 10m/s in the downward direction , what will be the height attained by the stone and how much time will it take to reach there ?
Answers
Answer:-
h = 1.25 m
t = 0.5 s
Given:-
u = 5m/s
g = 10m/s²
v = 0 m/s
To find :-
The maximum height reached.
Time take to reach their.
Solution:-
During an upward motion the final velocity (v)of the body become 0.
Now, first we have to calculate
first we have to calculateMaximum height:-
★
From, equation of motion under the influence of gravity.
→
→
→
Now,
we have to calculate time of ascent I.e, time to reach maximum height.
The formula for time of ascent is given by :-
★
Put the given value,
→
→
hence,
The maximum height reached by stone is 1.25 m and time taken to reach is 0.5s.
Answer:
Maximum height = 1.25 m
Time taken = 0.5 seconds
Explanation:
given that,
A stone is thrown in a vertically upward direction with a velocity of 5m/s
here,
we have,
initial velocity of the stone = 5 m/s
gravitational acceleration = 10 m/s²
let the maximum height that the stone can attain be h
so,
final velocity at h = 0 m/s [stone will stop at the maximum height}
now,
we have,
initial velocity(u) = 5 m/s
final velocity(v) = 0 m/s
gravitational acceleration(g) = -10 m/s² [against the gravitational force]
so
by the gravitational equation of motion,
v² = u² + 2gh
putting the values,
(0)² = (5)² + 2(-10)h
-20h + 25 = 0
-20h = -25
h = -25/-20
h = 5/4
h = 1.25 m
so
maximum height = 1.25 m
now,
we have,
initial velocity(u) = 5 m/s²
gravitational acceleration(g) = -10 m/s²
so,
by the gravitational equation of motion,
v = u + gt
putting the values,
0 = 5 + (-10)t
-10t + 5 = 0
-10t = -5
t = -5/-10
t = 1/2
t = 0.5 seconds
so,