Question

A stone is thrown in a vertically upward direction with a velocity of 5 m s-1. If the acceleration of the stone during its motion is 10m s-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there

Answer 1

Answer:

Given, u = 5m/s; v = 0 m/s; a = -10m/s

We know,

2as = v^2 - u^2

or, -20s = -25

or, s = 5/4 m = 125 cm = 1.25 m

Now, we know v = u + at

or, u + at = v

or, 5 - 10t = 0

or, -10t = -5

or, t = 1/2 s = 0.5s

Hence, height = 1.25 m and time = 0.5 s

Explanation:

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