Question

A stone is thrown in a vertically
upward direction with a velocity
of 5 ms. If the acceleration of the
stone during its motion is 10 ms?
in the downward direction, what
will be the height attained by the
stone and how much time will it
take to reach there?​ vaikunthapuramulo

Answer 1

To find the height attained -

$\rm \red{ {v}^{2} = {u}^{2} + 2as}$

$\implies \: s = \frac{ {v}^{2} - {u}^{2} }{2a} \\ \implies \: \frac{0 - 25}{2 \times ( - 10)} = 1.25$

t = 1/2=0.5

s=ut+1/2at ^2

s = 5(1/2) + 1/2(-10) ×1/4

s = (5/2-5/4) m

s = (10-5 / 4) m

s = 5/4 m

--------------answer = s, = 1.25m

Answer 2

Answer:

To find the height attained,

v2 = u2 + 2as

s = Height attained = (v2 - u2)/2a = (0 - 25)/(2 x -10) = 1.25 .

a is negative since it's direction is opposite to the direction of motion.

t = (v - u)/a = -5/-10 = 0.5 s.