A stone is thrown in a vertically upward direction with a velocity of 5ms .If the acceleration of the stone during its motion is 10ms in the downward direction, what will be the height attained by the the stone and how much time will it take to read there?
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The height it will attain is
1.25m
Time it will take is
0.5s
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Answer:
Given, initial velocity, u=5ms
−1
Final velocity, v=0
Since, u is upward & a is downward, it is a retarded motion.
∴a=−10ms
−2
Height attained by stone, s=?
Time take to attain height, t=?
(I) Using the relation, v^2−u^2 =2
as, we have
s=v^2 −u^2 /2a
=(0)^2 −(5)^2 /2×(−10)=1.25m
ii) Using the relation, v=u+at
0=5+(−10)t or
t=5/10=0.5s.
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