Question

A stone is thrown in a vertically upward direction with a velocity of 10 m/s. If the acceleration of the stone during its motion is 10 m /s2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

Answer 1

Answer:

1 sec

Explanation:

u=10 m/s , v=0 , a=-10 m /s2, s=? , t=?

as we all know

v^2 = u^2 +2as putting above value we will get s

                                       s= 5 m

now

     as v= u + at

we will get value of t as t = 1 sec

Answer 2

Answer:u=10 m/s , v=0 , a=-10 m /s2, s=? , t=?

as we all know

v^2 = u^2 +2as putting above value we will get s

                                       s= 5 m

now

     as v= u + at

we will get value of t as t = 1 sec