Question

A stone is thrown in a vertically upward direction with a velocity of 5m s-1 . If the acceleration of the stone during its motion is 10m s-2 in the downward direction what will be the height attained b the stone and how much time will it take to reach there ?

Answer 1

Answer:

2gh = v^2 - u^2

2.10m/s^2 .h = 0^2 - ( 5 )^2 m/s

20m/s^2 . h = 25 m/s

h = 25m/s / 20m/s^2

h = 1.25 m

t = v - u / g

= 0 - 5m/s / - 10m/s^2

= 0.5 s

hope it helps you..................

Answer 2

Answer:

Explanation:

Given:

u= 5m /s

A(during upwards direction)= -10m/s^2

At highest point it comes on rest

Therefore v =0

2as = v2 -u2

S = v2- u2 / 2a

S = 0 - (5)^2 / 2 ×(-10)

S = - 25/ -20

S = 5/ 4

S = 1.25 m

Time it will take to reach the highest point

V= u + at

0 = 5 + -10×t

-5 = -10t

t = -5/-10

t = 1/2

t= 0.5 s