Question

A stone is thrown in a vertically
upward direction with a velocity
5 m s-1. If the acceleration of the
stone during its motion is 10m s-2
in the downward direction, what
will be the height attained by the
stone and how much time will it
take to reach there?

please don't give direct answers
give step by step ​

Answer 1

Answer:

u = 5m/s

a = -10m/s [ negative value because force is against the gravity ]

v = 0m/s

h = ?

t = ?

in 1st , we have to find height :

2gh = v^2 - u^2

2*(-10m/s^2)*h = (0m/s)^2 - (5m/s)^2

-20m/s^2*h = -25m^2/s^2

h = -25m^2/s^2 / -20m/s^2

h = 1.25m

height = 1.25m , we have to find time :

t = v - u / g

t = 0m/s - 5m/s / -10m/s^2

t = 0.5s

time = 0.5 s

hope it helps...........

in 2nd case

Answer 2

hey buddy ,

which class you are studying ?