A stone is thrown in a vertically
upward direction with a velocity
of 5 ms-1. If the acceleration ofthe
stone during its motion is 10m s-2
in the downtoard direction, what
will be the height attained by the
stone and how much time will it
talce to reach there?
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Answer:
find t w. t.e vf= vi + at. height = vit+1/2 at^2
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