Question

A stone is thrown in a vertically
upward direction with a velocity of 5 m/s. If the acceleration of the
stone during its motion is 10 m/s in the downward direction,what will be the height attained by the stone and how much time will it
take to reach there?​

Answer 1

Answer:

initial velocity (u)=5 m/s

a= -10m/s² (  negative as downward)

final velocity (v) = 0 m/s (as ball comes to rest at highest position)

Now,

                         2as = v² - u²

                         2x(-10)xs = 0 - 5²

                         -20s   = - 25

                         s = -25/-20  = 5 / 4

                             = 1.25 m <-- height attained by stone

Now ,                     v = u + at

                             0 = 5 + (-10)t

                             t = -5/-10

                               = 0.5 s <-- time taken to reach highest point

               

Answer 2

Answer:

u=5 m/s

a= - 10m/s^2

v = 0 m/s

put the above values in the following equations of motion :

for maximum height : by using the equation of motion -> 2as = v^2-u^2

              we get the maximum height as 1.25 m

for time taken to reach that height: equation of motion -> v = u + at

          we get the time as 0.5s