Question

A stone is thrown in a vertically upward direction with a velocity of 4 m/s. If the acceleration of the stone is 10 m/s2 in the downward direction, calculate the height attained by the stone. *

Answer 1

Answer:

0.8 m

Explanation:

u = 4 m/s

a = -10 m/s²

v = 0 m/s

Using formula, v² = u² + 2as

⇒ (0)² = (4)² + 2(-10)s

⇒ 0 = 16 - 20s

⇒ 16 = 20s

⇒ s = 16/20 = 4/5 = 0.8 m

Hope this helps.....

Answer 2

Answer:

The maximum height attained by the stone is 0.08 m

Explanation:

u= initial velocity = 4 m/s

g= a = 10 m/s²

Vmax= u² / 2g

Vmax= 4² / 2 . 10

Vmax= 16 / 200

Vmax= 0.08 m

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