Question

A stone is thrown in a vertically upward direction with a velocity of 5 m s^-1 .if the acceleration of the stone during its motion is 10 m s^-2 in the downward direction ,what will be the height attained by the stone and how much time will it take to reach there?

Answer 1

Answer:

here is ur answer

Explanation:

Initial velocity,u=0

Final velocity,v=5m/s-¹

acceleration,a=-10m/s-¹

For, find height= v²-u²=2as

(5)²(0)²=2×(-10)×s

25=20s

s=25/20

s=1.25m

For, find t=v=u+at

5=0+(-10)t

5=10t

t=5/10

t=0.5s

Thus, the height is 1.25m and time is 0.5 sec.

hope it's help you

Answer 2

Answer:

Question -

A stone is thrown in a vertically upward direction with a velocity of 5 . if the acceleration of the stone during its mot-ion is 10  in the downward direction, what will be the height attained by the stone and how much will it take to reach there?

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