Question

A stone is thrown in a vertically
upward direction with a velocitu
of 5 ms. If the acceleration of the
stone during its motion is 10 ms?
in the downward direction, what
will be the height attained by the
stone and how much time will it
take to reach there?​

Answer 1

Given, initial velocity, u=5ms

−1

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion.

∴a=−10ms

−2

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v

2

−u

2

=2as, we have

s=v

2

−u

2

/2a

=(0)

2

−(5)

2

/2×(−10)=1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s

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Answer 2

Answer:

Given, initial velocity, u=5m/s

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion.

∴a=−10m/s

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v²-u²= 2as

we have

S= v²-u²/2a

S= (0)² -(5)²/ 2×(−10)=1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s

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