Question

A stone is thrown in a vertically
upward direction with a velocity
of 5 ms. If the acceleration of the
stone during its motions is 10 ms
in the downward direction, What
will be the height attained by the
stone and how much time will it
take to reach there?
​

Answer 1

u=5

a=-10

v=0

there after using equations of motion

Answer 2

Answer:

Height needs to be reached = 2.5m

Explanation:

Given:

Initial Velocity, u = 5m/s

Acceleration = 10m/s^2

Procedure:

Let's assume 'v' to be the final velocity and 's' be the height attained.

let highest point be, v = 0

Let's use the equation of motion:

v = u + at

→ 0 = 5 -10t

→ 10t = 5

→ t = 1/2 seconds

Now, we know that:

$\bf \implies \: s = ut + \dfrac{1}{2} {(at)}^{2}$

$\implies \sf \: s = 5 \times \dfrac{1}{2} + \dfrac{1}{2} \times ( - 10) \times \bigg(\dfrac{1}{2} { \bigg)}^{2}$

$\implies \sf \: s = \dfrac{5}{2} m$

→ S = 2.5