Question

A stone is thrown in a vertically upward direction with a velocity of 6 m/s. If the

acceleration of the stone during its motion is 10 m/s2 in the downward direction,

what will be the height attained by the stone and how much time will it take to

reach there?​

Answer 1

Step-by-step explanation:

Given, initial velocity, u=5ms

−1

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion.

∴a=−10ms

−2

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v

2

−u

2

=2as, we have

s=v

2

−u

2

/2a

=(0)

2

−(5)

2

/2×(−10)=1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s

Answer 2

Answer:

v2-u2=2as

v=0,u=6,a=-10 and s=?

so 36=20s

so s is equal to 1.8 meters

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