Question

A stone is thrown in a vertically
upward direction with a velocity
of 5 ms. If the acceleration of the
stone during its motion is 10 m s-2
in the downward direction, what
will be the height attained by the
stone and how much time will it
take to reach there?​

Answer 1

Answer:

Given, initial velocity, u=5ms^−1

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion.

∴a = −10ms^−2

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v² - u² = 2as, we have

s = v² - u²/2a

s = 0 - 5ms^-1 / 2 x -10 m/s²

s = 1.25 m

ii) Using the relation, v = u + at, we have

at = v - u

t = (v - u) / a

t = -5 m/s / -10 m/s²

t = 0.05s

So, Height is 1.25 meter

Time is 0.05 second

I hope it may help you.