Question

A stone is thrown in a vertically upward direction with a velocity of 15 ms-1. If the acceleration of the stone during its motion is 10 ms-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

Answer 1

Answer:

your answer

Explanation:

Given, initial velocity, u=5ms  

−1

 

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion.  

∴a=−10ms  

−2

 

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v  

2

−u  

2

=2as, we have

s=v  

2

−u  

2

/2a

=(0)  

2

−(5)  

2

/2×(−10)=1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s