A stone is thrown in a vertically upward direction with a velocity of 5ms^-1 if the acceleration of the stone during the motion is 10 ms^-2 in the downward direction what will be height attained by the stone and how much time will it take to reach there
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Explanation:
Given, initial velocity, u=5ms
−1
Final velocity, v=0
Since, u is upward & a is downward, it is a retarded motion.
∴a=−10ms^−2
Height attained by stone, s=?
Time take to attain height, t=?
(i) Using the relation, v² −u² =2as, we have
s=v² −u² /2a
=(0)² −(5)² /2×(−10)=1.25m
(ii) Using the relation, v=u+at
0=5+(−10)t or
t=5/10=0.5s
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