Question

A stone is thrown in a vertically upward direction with a velocity of 5ms^-1 if the acceleration of the stone during the motion is 10 ms^-2 in the downward direction what will be height attained by the stone and how much time will it take to reach there
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Answer 1

Answer:

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Answer 2

Explanation:

Given, initial velocity, u=5ms

−1

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion.

∴a=−10ms^−2

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v² −u² =2as, we have

s=v² −u² /2a

=(0)² −(5)² /2×(−10)=1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s

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