Question

a stone is thrown in a vertically upward direction with a velocity of 5 metre per second is the acceleration of the stone during its motion is 10 M per second square in the downward Direction What will be the height attained by the stone and how much time will it take to reach there

Answer 1

Here your answer ༼ つ ◕_◕ ༽つ:-

(See above image for more understanding)

Let its initual velocity=u
which is = 5m/s
Accleration (due to gravity)=10m/ sq. second
After reaching maximum height final velocity will be= 0m/s
v (final velocity)=0m/s

ACCORDING TO NEWTON'S THIRD EQUATION OF MOTION ༼ つ ◕_◕ ༽つ :-

$2as = {v}^{2} - {u}^{2}$
Stone is going upward so its acceraltion due to gravity will be negative.
a= (-10)m/ sq. second

$2 \times ( - 10) \times s = {0}^{2} - {5}^{2} \\ - 20 \times s = 0 - 25 \\ - 20 \times s = - 25 \\ s = - 25 \div - 20 \\ s = 25 \div 20 \\ s = 5 \div 4 \\ s = 1.25metre$
Here s is the DISTANCE.

Time=?

ACCORDING TO NEWTON'S FIRSR LAW OF MOTION ༼ つ ◕_◕ ༽つ :-

v= u+at
$0 = 5 + ( - 10) \times t \\ 0 = 5 - 10t \\ - 10t = - 5 \\ t = - 5 \div ( - 10) \\ t = 5 \div 10 \\ t = 1 \div 2 \\ t = 0.5seconds$
Here t is the TIME.

HOPE IT HELPS YOU!

༼ つ ◕_◕ ༽つ

^-^

Answer 2

Answer is 0.5......