a stone is thrown in a vertically upward direction with a velocity of 5m per second. if the acceleration of the stone during its motion in 10 M per second square in the downward Direction What will be the height attained by the stone and how much time will it take to reach there there?
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u= 5m per second
a=10ms-2
4=0
height=distance=s
v2-u2=2as
02-52=2*-10*s
s=-25/-20=5/4=1.25m
using v=u+at
we get,0=5+10*t
10t=-5
t=-5/10=-0.5s.
a=10ms-2
4=0
height=distance=s
v2-u2=2as
02-52=2*-10*s
s=-25/-20=5/4=1.25m
using v=u+at
we get,0=5+10*t
10t=-5
t=-5/10=-0.5s.
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