Question

A stone is thrown in a vertically upward direction with a velocity of 5ms^-1.If The acceleration of the stone during its motion is 10ms^-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

Answer 1

Solution
Here, initial velocity, u= 5m/s

acceleration= -10m/s^2 [negative acceleration]

final velocity, v= 0m/s


Now, v= u+ at

=> 5= 0+ 10t

=> t= 1/2 sec= 0.5 second.

Now, s= ut+ 1/2 at^2

= 5*1/2+ 1/2(-10) (1/2)^2

= 5/2 -5/4

= (10-5)4

s = 5/4 m

Answer 2

Explanation:

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