A stone is thrown in a vertically upward direction with a velocity of 5ms^-1.If The acceleration of the stone during its motion is 10ms^-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?
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Here, initial velocity, u= 5m/s
acceleration= -10m/s^2 [negative acceleration]
final velocity, v= 0m/s
Now, v= u+ at
=> 5= 0+ 10t
=> t= 1/2 sec= 0.5 second.
Now, s= ut+ 1/2 at^2
= 5*1/2+ 1/2(-10) (1/2)^2
= 5/2 -5/4
= (10-5)4
s = 5/4 m
Here, initial velocity, u= 5m/s
acceleration= -10m/s^2 [negative acceleration]
final velocity, v= 0m/s
Now, v= u+ at
=> 5= 0+ 10t
=> t= 1/2 sec= 0.5 second.
Now, s= ut+ 1/2 at^2
= 5*1/2+ 1/2(-10) (1/2)^2
= 5/2 -5/4
= (10-5)4
s = 5/4 m
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