A stone is thrown in a vertically upward direction with a velocity of 5 m s-1. If the acceleration
of the stone during its motion is 10 m s–2 in the downward direction, what will be the height
attained by the stone and how much time will it take to reach there?
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Explanation:
A stone is thrown in vertically upward direction with a velocity of 5 m s − 1. If the acceleration of the stone during its motion is 1 0 m s − 2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there
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Explanation:
Initially velocity of the stone = 5 m/s
Acceleration = g = 10 m/s²
Final velocity at the top = 0 m/s
Applying equations of motion,
v = u + gt
=> 0 m/s = 5m/s - 10 m/s² × t
=> 10 t = 5
=> t = 5/10 = 0.5 s
v² = u² + 2gH
=> 0 = 5² m²/s² + 2 × (- 10 m/s²) × H
=> 25 - 20H = 0
=> H = 25/20 = 1.25 m
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