Question

a stone is thrown in a vertically upward direction with a velocity of 5m/s . if the acceleration of the stone during its motion is 10 m/s2 in the downward direction ,what will be the height attained by the stone and how much time will it take to reach there ?

Answer 1

Hi.........

U= 5m per second

a=10ms-2

4=0

height=distance=s

v2-u2=2as

02-52=2*-10*s

s=-25/-20=5/4=1.25m

using v=u+at

we get,0=5+10*t

10t=-5

t=-5/10=-0.5s.


Hope this helps u!!