Question

A stone is thrown in a vertically upward direction with a velocity of 5m/s. If the
acceleration of the stone during the motion is 10m/s2 in the downward direction,
what will be the height attained by the stone and how much time will it take to
reach there?

Answer 1

1.25m will be the height attained by the stone and 0.5 seconds will it take to reach there

Answer 2

Hey mate!!!

Distance (s) = (v^2 - u^2)/2a
here u is 5
a is -10 (because it is in opposite direction so we write -10)
v is 0 because final velocity will be zero when it stops.
so
$s = \frac{ {v}^{2} - {u}^{2} }{2a } \\ s = \frac{0 {}^{2} - 5 {}^{2} }{2 \times - 10} \\ s = \frac{0 - 25}{ - 20} \\ s = \frac{ - 25}{ - 20} \\ s = \frac{5}{4} \\ s = 1.25metre$

Now

$t = \frac{v - u}{a } \\ t = \frac{ - 5}{ - 10} \\ t = \frac{1}{2} \\ t = 0.5seconds$
So time is 0.5 second
Hope it helps dear friend ☺️✌️✌️