Question

A stone is thrown in a vertically upward direction with a speed of 10m/s. How much time will it take to reach the maximum height before it starts falling again? Was the stone under accelerated motion or decelerated motion?
[Hint: Acceleration due to gravity.g=10m/s²]
please tell fast
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Answer 1

Explanation:

Given, initial velocity, u=5ms−1

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion. 

∴a=−10ms−2

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v2−u2=2as, we have

s=v2−u2/2a

=(0)2−(5)2/2×(−10)=1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s

hope it helps you out.