Question

A stone is thrown in a vertically upward direction with a velocity of 5ms-¹.If the acceleration of the stone during its motion is 10m s-² in downward direction,what will be the height attained by the stone and how much time will it take to reach there?​

Answer 1

Answer:

If the acceleration of the stone during its motion is 10 m s-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there? Therefore, the stone reaches a maximum height of 1.25 meters in a timeframe of 0.5 seconds

Answer 2

Answer:

U=5m/s

a=10m/s^2

v=0m/s

so the kinemetic formula is

2as=v^2-u^2

2×10×s=-25m/s

10s=-25

s= -25/10

s= -5/2

s=. - 2.5m

now distance is always positive thus

distance = 2.5m