a stone is thrown in a vertically upward direction with a velocity of 5 metre per second if the acceleration of the stone during it's motion is 10 per second aware in the downward direction what will be the height attained by the stone and how much time will it take to reach there
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Explanation:
Given, initial velocity, u=5ms-¹
Final velocity, v=0
Since, u is upward & a is downward, it is a retarded motion.
∴a=−10ms-²
Height attained by stone, s=?
Time take to attain height, t=?
(i) Using the relation, v²–u²=2as, we have
s=v²−u²/2a
=(0)²−(5)²/2×(−10)=1.25m
(ii) Using the relation, v=u+at
0=5+(−10)t or
t=5/10=0.5 sec
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