a stone is thrown in a vertically upward direction with a velocity 5m.s-1 . if the acceleration of the stone during its motion is 10 m.s-2 in downward direction What will be the height attained by the stone and how much time will be taken to reach there
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HEY!!
____________________________
u = 5m/sec
a = 10m/sec^2
v = 0 (at the maximum height)
s = h ?
t = ?
____________________________
2as = v^2 - u^2
s = v^2 - u^2 / 2a
s = 0^2 - 5^2 / 2 × (-10)
s = 0 - 25 / -20
s = -25 / -20
s = 1.25m
____________________________
v = u + at
at = v - u
t = v - u / a
0 - 5 / -10
5 / 10
t = 0.5sec
____________________________
u = 5m/sec
a = 10m/sec^2
v = 0 (at the maximum height)
s = h ?
t = ?
____________________________
2as = v^2 - u^2
s = v^2 - u^2 / 2a
s = 0^2 - 5^2 / 2 × (-10)
s = 0 - 25 / -20
s = -25 / -20
s = 1.25m
____________________________
v = u + at
at = v - u
t = v - u / a
0 - 5 / -10
5 / 10
t = 0.5sec
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