A stone is thrown in a vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 m/s in the downward direction , what will be the height attained by the stone and how much time will it take to reach there ?
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Answer:
Explanation:
Given, initial velocity
u = 5 m s − ¹, acceleration a = − 10 m s − ²
Let 'v' be the final velocity and 's' be the height attained.
At the highest point, v = 0
Using third equation of motion,
v ²= u ² + 2 a s , 0 = 5 2 + [ 2 ×( − 10 ) × s ]
⇒ s = 1.25 m
Hence the height attained by the coin is 1.25 m.
Let the time taken be t.
Using the first equation of motion,
v = u + at
0 = 5 - 10t ⇒ t = 0.5 s
∴ Time Taken by the coin is 0.5 s.
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