Question

A stone is thrown in a vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 m/s in the downward direction , what will be the height attained by the stone and how much time will it take to reach there ?

Answer 1

Answer:

Explanation:

Given, initial velocity  

u = 5 m s − ¹, acceleration   a = − 10   m s − ²

Let 'v' be the final velocity and 's' be the height attained.

At the highest point,  v = 0

Using third equation of motion,  

v ²= u ² + 2 a s ,  0 = 5 2 + [ 2 ×( − 10 ) × s ]

⇒  s = 1.25 m

Hence the height attained by the coin is 1.25 m.

Let the time taken be t.

Using the first equation of motion,

v = u + at

0 = 5 - 10t ⇒ t = 0.5 s        

∴ Time Taken by the coin is 0.5 s.