Question

A stone is thrown in a vertically upward direction with a velocity of 19.6 m/s for 4 sec. Calcualte the max height acheived nby the stone and the time taken to reach upto the max height.

Answer 1

${v}^{2} - {u}^{2} = 2gh$
$- {19.6}^{2} = 20h$
$h = 19.2meters$
$t = \sqrt{ \frac{2h}{g} }$
$t = 2(approx..)$
NOW,

$t = 4s \: means \: time \: of \: flight = 4s$
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