A stone is thrown in a vertically upward direction with a velocity of 5ms-¹.if the acceleration of the stone during its motion is 10ms-² in the downward direction. What will be the hight attained by the stone and how much time will it take to reach there?
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Answered by
8
hey mate
here is your answer
h=u²/2g
=5²/2*10
=25/20
=1.25 m
t=u/g
=5/10
=0.5 s
here is your answer
h=u²/2g
=5²/2*10
=25/20
=1.25 m
t=u/g
=5/10
=0.5 s
Answered by
3
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