Question

a stone is thrown in a vertically upward direction with a velocity of 5m/s. If the acceleration of the stone during its motion is 10m/s^2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there? ​

Answer 1

u=5

v=0

a=-10

s=v^2-u^2/2a

=0-25/-20=5/4=1.25m

in order to find time....

v=u+at

v-u=at

v-u/a=t

0-5/-10=t

thus, t=0.5 s

hope it helps uuh ☺☺