Question

A stone is thrown in a vertically upward direction with the velocity of 5 metre per second. If the acceleration of the stone during the motion of 10 metre per second square in downward direction, what will be the height attained by the stone and how much time will it take to reach there

Answer 1

Answer:time required will be 0.5 seconds and height attained will be 1.2m

Explanation:

V=u+at ...v=0 ; u=5; a=-10

Then apply s=ut+1/2at×t and find s

Answer 2

as given that ,

u = 5 metre per sec.

a = - 10 metre per sq sec.

v = 0.

by using v= u +at

0 = 5 + (-10)t

= t = 1/2

that is , time that will take is 0.5 sec.

now , by using s = ut + 1/2 at^2.

s = 5(1/2) + 1/2(-10) ×1/4

s = (5/2-5/4) m

so , s = 5/4

that is , s = 1.25metre

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