Question

a stone is thrown in a virtual upward direction with a velocity of 72 kilometre per hour if the acceleration of the stone during its motion is 10 metre square in the downward Direction What will be the height attended by the stone and how much time will it take to reach there​
(plz tell fast )

Answer 1

Answer:

ok like me . Iam new commer ok tha

nks total time taken is 0.5 s and distance is 1.25m

Answer 2

Answer:

Given,

u=72km/hr

after calculating we will get,

u=20m/s^2

v=0

a=10m/s

t=?

s=?

v^2-u^2=2as

0^2-(20)^2=2×10×s

400=20×s

400/20=s

20m=s

Time:

a=v-u/t

10=0-20/t

10=-20/t

10t=20

t=20/10

t=21

a=20m, t=2s

Thank you. ..........