Question

a stone is thrown in vertically upward direction under uniform acceleration due to gravity.if the stone is at same height at 1st second and 7th second from ground,the height at 3rd and 5th second is

Answer 1

let the height covered in first case be y,
and initial velocity be u
assuming origin to be at ground

so
y = ut -½gt²
ATQ-
y(1) = y(7)
or
u - ½g = 7u - ½g•49
or
-5 + 245 = 6u
or
u = 40 ms-1
so y(3) = 40•3 - 5•9
= 75 m above the ground.
and
y(5) = 40•5 - 5•25
= 75 m above the ground.

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