A stone is thrown in vertically upward direction with a velocity of 5 ms-1. If the acceleration of the stone during its motion is 10 ms-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there? A. Height= 1.25 m and time = 0.5 s B. Height: 2.5 m and time = 0.5 s C. Height= 2.5 m and time = 0.05 s D. Height= 1.25 m and time = 0.05 s
Answers
Answer:
Explanation:
Solution,
Here, we have
Initial velocity, u = 5 m/s
Final velocity, v = 0
Acceleration, a = 10 m/s²
To Find,
Height attained, s = ?
Time taken, t = ?
According to the 3rd equation of motion,
We know that,
v² - u² = 2as
So, putting all the values, we get
⇒ v² - u² = 2as
⇒ (0)² - (5)² = 2 × 10 × s
⇒ 25 = 20s
⇒ 25/20 = s
⇒ s = 1.25 m.
Hence, the height attained is 1.25 m.
Now, we will find time taken,
According to the 1st equation of motion,
v = u + at
So, putting all the values again, we get
⇒ v = u + at
⇒ 0 = 5 + 10 × t
⇒ 5 = 10t
⇒ 5/10 = t
⇒ t = 0.5 seconds.
Hence, the time taken is 0.5 seconds.
Here, 1st option i.e, Height= 1.25 m and time = 0.5 s is correct.
Question :-
▪ A stone is thrown in vertically upward direction with a velocity of 5 ms-1. If the acceleration of the stone during its motion is 10 ms-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?
A. Height= 1.25 m and time = 0.5 s
B. Height: 2.5 m and time = 0.5 s
C. Height= 2.5 m and time = 0.05 s
D. Height= 1.25 m and time = 0.05 s
_______________________________
Given :-
- Initial velocity =5m/s
- Acceleration =10m/s²
- Final velocity =0m/s
_______________________________
To Find:-
- Height attained by stone.
- Time taken by stone.
_______________________________
Solution :-
By using 3rd equation of motion
∴The distance covered by stone is 1.25m.
And ,
To find time taken by Stone
so,
By using 1st equation of motion
☛ v =u+at
☛ 0=5+10×t
☛ t=5/10
☛ t=1/2
☛ t=0.5s
∴ The time taken by stone is 0.5s
Hence,
option (A) is the correct answer.