Physics, asked by sanjithvihanush, 9 months ago

A stone is thrown in vertically upward direction with a velocity of 5 ms-1. If the acceleration of the stone during its motion is 10 ms-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there? A. Height= 1.25 m and time = 0.5 s B. Height: 2.5 m and time = 0.5 s C. Height= 2.5 m and time = 0.05 s D. Height= 1.25 m and time = 0.05 s

Answers

Answered by VishalSharma01
121

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 5 m/s

Final velocity, v = 0

Acceleration, a = 10 m/s²

To Find,

Height attained, s = ?

Time taken, t = ?

According to the 3rd equation of motion,

We know that,

v² - u² = 2as

So, putting all the values, we get

⇒ v² - u² = 2as

⇒ (0)² - (5)² = 2 × 10 × s

⇒ 25 = 20s

⇒ 25/20 = s

s = 1.25 m.

Hence, the height attained is 1.25 m.

Now, we will find time taken,

According to the 1st equation of motion,

v = u + at

So, putting all the values again, we get

⇒ v = u + at

⇒ 0 = 5 + 10 × t

⇒ 5 = 10t

⇒ 5/10 = t

t = 0.5 seconds.

Hence, the time taken is 0.5 seconds.

Here, 1st option i.e, Height= 1.25 m and time = 0.5 s is correct.

Answered by MystícPhoeníx
150

Question :-

▪ A stone is thrown in vertically upward direction with a velocity of 5 ms-1. If the acceleration of the stone during its motion is 10 ms-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

A. Height= 1.25 m and time = 0.5 s

B. Height: 2.5 m and time = 0.5 s

C. Height= 2.5 m and time = 0.05 s

D. Height= 1.25 m and time = 0.05 s

_______________________________

Given :-

  • Initial velocity =5m/s

  • Acceleration =10m/s²

  • Final velocity =0m/s

_______________________________

To Find:-

  • Height attained by stone.
  • Time taken by stone.

_______________________________

Solution :-

By using 3rd equation of motion

v {}^{2}  = u {}^{2}  + 2as \\  \\ 0 { }^{2}  = 5 {}^{2}  + 2 \times 10 \times s \\ 0 = 25 + 20 \times s \\  \\ s =  \frac{25}{20}  \\  \\ s = 1.25m

The distance covered by stone is 1.25m.

And ,

To find time taken by Stone

so,

By using 1st equation of motion

☛ v =u+at

☛ 0=5+10×t

☛ t=5/10

☛ t=1/2

☛ t=0.5s

∴ The time taken by stone is 0.5s

Hence,

option (A) is the correct answer.

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