A stone is thrown in vertically upward direction with a velocity of 5ms.If the acceleration of the stone during its motion is 10ms in the downward direction,what will be the height attained by the stone and how much time will it take to reach there?
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Answered by
3
five metre distance
Subhammodi:
ok no problem
Answered by
19
Here we have ,
initial velocity = u = 5m/s
final velocity = v = 0m/s
acceleration = a = -10m/s²
distance = height = s = ?
time = t = ?
v² - u² = 2as
(0)² - (5)² = 2(-10)s
0 - 25 = -20S
-25/-20 = S
5/4 = S
1.25 m = s
so height is 1.25m
a = v-u/t
at = v-u
t = v-u/a
t = 0-5/-10
t = -5/-10
t = 5/10
t = 0.5 s
Time is 0.5 second
initial velocity = u = 5m/s
final velocity = v = 0m/s
acceleration = a = -10m/s²
distance = height = s = ?
time = t = ?
v² - u² = 2as
(0)² - (5)² = 2(-10)s
0 - 25 = -20S
-25/-20 = S
5/4 = S
1.25 m = s
so height is 1.25m
a = v-u/t
at = v-u
t = v-u/a
t = 0-5/-10
t = -5/-10
t = 5/10
t = 0.5 s
Time is 0.5 second
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